The future amount for a compound interest can be calculated by the formula
![\text{ A= p(1+}(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/hnq87vfofaz04zm1jtsgiizd6p6b5r18b7.png)
Where A = Final amount
p = initial principal balance
r = interest rate
n = number of times interest is applied per period
t = number of times period elapses
For this question,
p = $10,000
r = 6%
The interest is compounded semi-annually, which means twice every year, hence
n= 2
t = 16
substituting the values into the formula. we have
![\begin{gathered} A\text{ = 10,000(1 +}(0.06)/(2))^{2\text{ x 16}} \\ A=10,000(1+0.03)^(32) \\ A=10000(1.03)^(32) \\ A=10.000(2.57508275) \\ A=25,750.8275 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/w4le3m57pvdolmmewa9trupd0txb0woplq.png)
A = $25,750.
Hence, in 16 years, the bond will worth