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F(1)=6 f(n) =1/3f(n-1)what are the first 5 terms?

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\begin{gathered} f(1)=6 \\ f(n)=(1)/(3)f(n-1) \end{gathered}

f(n-1) is the term previous to n.

As you know the 1st term, use to find the 2nd term :


\begin{gathered} f(2)=(1)/(3)f(2-1) \\ \\ f(2)=(1)/(3)f(1) \\ \\ f(2)=(1)/(3)(6) \\ \\ f(2)=2 \end{gathered}

Use 2nd term to find the 3rd term:


\begin{gathered} f(3)=(1)/(3)(2) \\ \\ f(3)=(2)/(3) \end{gathered}

Use 3rd term to find 4th term:


\begin{gathered} f(4)=(1)/(3)\cdot(2)/(3) \\ \\ f(4)=(2)/(9) \end{gathered}

Use 4th term to find 5th term:


\begin{gathered} f(5)=(1)/(3)\cdot(2)/(9) \\ \\ f(5)=(2)/(27) \end{gathered}

Then, the correct answer is A. 6,2, 2/3, 2/9, 2/27

User Chris Eberle
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