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Graph one complete cycle of y = -sec(2)+3. and list out your critical values points. Include asymptotes, if any.

Graph one complete cycle of y = -sec(2)+3. and list out your critical values points-example-1

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Solution:

Given:


y=-sec((x)/(4))+3

The graph of the above equation is shown below:

The critical values points are


Graph one complete cycle of y = -sec(2)+3. and list out your critical values points-example-1