Answer
(a) 1/6
(b) 2/3
Step-by-step explanation
In a single roll of a die, the sample space is {1, 2, 3, 4, 5, 6}
(a) The odds in favour of rolling a ''five''.
The possible outcome of five is 1.
Therefore, the odds in favour of rolling a ''five'' will be:
![P(rolling\text{ }a\text{ }five\rbrace=(1)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/3yxttf7a8l2m12wxvs2kq94558kc1z3tfh.png)
(b) The Odds Against rolling a multiple of "three".
Multiple of three is {3, 6).
![P(multiple\text{ }of\text{ }three)=(2)/(6)=(1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/11ap8nnvt2c2snmo4nsevp2h9b5d3v72qs.png)
Hence, the odds against rolling a multiple of three will be:
![1-(1)/(3)=(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/fvob2dmdk8ld18rawwe7bk3ro8m8o283so.png)