Question

A and B are identical uncharged spheres. If sphere A is given a charge of +q and then brought into contact with sphere B, the charge on sphere A after separation will be(a) +q (b) +q/2 (c) 0 (d) -q

Answer 1

Given:

Charge in sphere A = +q

Where sphere A and shere B are identical uncharged spheres.

When the shere A given a charge of +q is brought into contact with sphere B, let's find the charge on shere A after seperation.

Here, since the two spheres are identical, when brought in contact with each other, they will end up with the same charge after seperation.

Before sepration, the total charge will be +q.

After seperation, the charge on both spheres will be equal.

This means the charge on sphere A (+q) will be divided exactly by half.

Therefore, the charge on sphere A after seperation will be:

`(+q)/(2)`

ANSWER:

(b) +q/2