Question

A block of mass of 9kg is hit by a force of magnitude F which causes the block to have an acceleration of magnitude a. If a second block with mass of 45 kg is hit by the dame force, then which of these is the magnitude of acceleration of the second block?A) 2.2361aB)aC) one/25 of aD) one fifth of aE) 25a

Answer 1

We are given that a mass of 9kg is hit by a force "F". According to Newton's second law we have:

`F=ma_1`

Plugging in the values we get:

`F=(9kg)a_1`

Now, we are given that a second block with a mass 45 kg is hit by the same force. Using newton's second law we get:

`F=(45kg)a_2`

Now, we divide both equations:

`(F)/(F)=((9kg)a_1)/((45kg)a_2)`

Now, we cancel out the "F":

`1=((9kg)a_1)/((45kg)a_2)`

Now, we multiply both sides by "a2":

`a_2=((9kg)a_1)/((45kg))`

Simplifying we get:

`a_2=(1)/(5)a_1`

Therefore, the acceleration of the second block is one-fifth of the acceleration of the first block.