Question

The solubility of methane in water at 20° C and 100kPa is 0.026 g/L. If the temperature remains constant, what will the solubility of this Gas be at the following pressures?a. 60kPAb. 180kPa

Answer 1

For this question, we will be using Henry's law, which is a law that shows the relationship between pressure change and solubility change at constant temperature, the formula for this law is:

S1/P1 = S2/P2

We have:

S1 = 0.026g/L

P1 = 100 kPa

S2 = ?

P2 = for letter A, 60 kPa

Now we add these values into the formula:

0.026/100 = S2/60

0.00026 * 60 = S2

S2 = 0.0156g/L, this is for letter A

For letter B

0.026/100 = S2/180

0.00026 * 180 = S2

S2 = 0.0468g/L, this is for letter B