Answer:
After 15 years, there will be 3.150 grams of substance.
Explanation:
Remember that the general exponential function for decay is:
![Q(t)=Q_0e^(kt)](https://img.qammunity.org/2023/formulas/mathematics/college/ce4co9g21fb9zwv14zu8hl2j1ul7ctwhzu.png)
Where Q(t) is the quantity after t years, and Qo is the initial quantity.
Since we know that there were 10 grams initially and that after 9 years only 5 grams remain, we can say that:
![5=10e^(9k)](https://img.qammunity.org/2023/formulas/mathematics/college/3ksev8embie8bz0t9prm5ljcreox0bv8nv.png)
Solving for k,
![\begin{gathered} 5=10e^(9k) \\ \rightarrow(5)/(10)=e^(9k) \\ \\ \rightarrow0.5=e^(9k)\rightarrow\ln(0.5)=9k \\ \\ \Rightarrow k=(\ln(0.5))/(9) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2ce73i0ya3qjuvq67wmzhwyvhzjksgq2w2.png)
This way, we'll have that:
![Q(t)=10e^{(\ln(0.5))/(9)t}](https://img.qammunity.org/2023/formulas/mathematics/college/x0nlx5xm8xbjq9r7p0291raovggwl9djdt.png)
We can calculate how much substance is left after 15 years as following:
![\begin{gathered} Q(15)=10e^{\frac{\operatorname{\ln}(0.5)}{9}*15} \\ \\ \rightarrow Q(15)=3.150 \end{gathered}]()
We can conclude that after 15 years, there will be 3.150 grams of substance.