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Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes. If 6 adult smartphone users are randomly selected, find theprobability that exactly 3 of them use their smartphones in meetings or classes

User Seif Sayed
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Given that the sample contains 6 students, so the sample size will be,


n=6

Let the success of the experiment is defined as the event that a randomly selected adult uses a smartphone in meetings or classes. And 'x' be the random variable representing the number of successes.

Given that 58% of the adults use a smartphone in meetings and classes. So there will be 58% chance that a randomly selected adult uses a smartphone in meetings and classes.

So, the probability of success will be,


\begin{gathered} p=58\text{ percent} \\ p=(58)/(100) \\ p=0.58 \end{gathered}

Then, the probability of getting exactly 'x' successes, is given by,


P(X=x)=^nC_x\cdot p^x\cdot(1-p)^(n-x)

So, the probability of exactly 3 successes will be,


\begin{gathered} P(X=3)=^6C_3\cdot(0.58)^3\cdot(1-0.58)^(6-3) \\ P(X=3)=20\cdot(0.195112)\cdot(0.074088) \\ P(X=3)\approx0.2891 \\ P(X=3)\approx28.91\text{ percent} \end{gathered}

Thus, there is 28.91% probability that exactly 3 of them use their smartphones in meetings or classes.

User AvadhP
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