Question

Please help me with this question I’m confused on how to do it

Answer 1

`\Delta H\text{ = -471.6 KJ}`

Step-by-step explanation:

Here, we want to get the enthalpy of reaction for the given reaction

In order to get this, we shall be using the heat of the formation of the products and reactants

For a molecule like oxygen that contains an atom of the same element, the heat of formation is written as zero

The enthalpy of reaction can be written as follows:

`\text{ }\Delta H\text{ = Heat of formation of products - heat of formation of reactants}_{}_{}`

The heat of formation of magenetite Fe3O4 is -1118.4 KJ/mol

The heat of formation of Fe2O3 is -824.2 KJ/mol

The enthalpy of reaction is thus:

`\begin{gathered} \Delta H\text{ = 6(-824.2) - (0 + 4(-1118.4))} \\ \Delta H\text{ = -4945.2 + 4473.6} \\ \Delta H\text{ = -471.6 KJ} \end{gathered}`