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Determine whether figure ABCD is a parallelogram. (let me know if you need to see the drop down options)

Determine whether figure ABCD is a parallelogram. (let me know if you need to see-example-1
User Zevi
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1 Answer

4 votes

Given:

A(1,2)

B(3,4)

C(3,-1)

D(1,-3)

Solution:

We are asked to justify the argument using the slope formula and the distance formula.

Slope Formula:


m=(y_2-y_1)/(x_2-x_(`1))

Distance Formula:


d=\sqrt[]{(x_2_{}-x_1)^2^{}_{}+(y_2-y_1_{})^2}

Now, we will use the given to find the slope and the distance inorder to answer the questions.

For the slopes:


\begin{gathered} m_(AB)=(4-2)/(3-1) \\ m_(AB)=(2)/(2) \\ m_(AB)=1 \end{gathered}


\begin{gathered} m_(CD)=(-3+1)/(1-3) \\ m_(CD)=(-2)/(-2) \\ m_(CD)=1 \end{gathered}

The slopes of AB and CD are equal.

For the distances:


\begin{gathered} d_(AB)=\sqrt[]{(3_{}-1_{})^2_{}+(4_{}-2_{})^2} \\ d_(AB)=\sqrt[]{2^2+2^2} \\ d_(AB)=\sqrt[]{8} \\ d_(AB)=2\sqrt[]{2} \end{gathered}
\begin{gathered} d_(CD)=\sqrt[]{(1_{}-3_{})^2_{}+(-3_{}+1_{})^2} \\ d_(CD)=\sqrt[]{(-2)^2+(-2)^2} \\ d_(CD)=\sqrt[]{8} \\ d_(CD)=2\sqrt[]{2} \end{gathered}

ANSWER:

Yes, ABCD is a paralellogram.

AB is equal to CD and the slopes of AB and CD are equal, so one pair of opposite sides is both parallel and congruent.

User Zhenhir
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