Question

Solve the equation for all the values of x by completing the squarex²+67=18x

Answer 1

`\begin{gathered} x^2+\text{ 67 -18x = 0} \\ x^2\text{ - 18x + 67 + 14 = 14} \\ x^2\text{ -18x + 81 = 14} \\ (x\text{ -9)(x-9) = }14 \\ (x-9)^2\text{ }=\text{ 14} \\ x-9=\text{ }\pm\text{ }\sqrt[]{14} \\ x\text{ = }\pm\sqrt[]{14}\text{ + 9 } \end{gathered}`

So the answer is

`x=\sqrt[]{14}+9\text{ o }x=-\sqrt[]{14}+9\text{ }`