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Passing through (2, -4) and parallel to the line whose equation is y = - 4x + 9; slope-intercept form

User Jarekczek
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1 Answer

3 votes

Answer

y = -4x + 4

Step-by-step explanation

The general form of the equation in point-slope form is

y - y₁ = m (x - x₁)

where

y = y-coordinate of a point on the line.

y₁ = This refers to the y-coordinate of a given point on the line

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

x₁ = x-coordinate of the given point on the line

We will then simplify this to obtain the equation of the line in slope-intercept form.

Point = (x₁, y₁) = (2, -4)

For the slope, two parallel lines always have the same slopes

The slope and y-intercept form of the equation of a straight line is given as

y = mx + b

where

y = y-coordinate of a point on the line.

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

b = y-intercept of the line.

y = -4x + 9

Slope = m = -4

So, for our required line,

Point = (x₁, y₁) = (2, -4)

Slope = m = -4

Recall,

y - y₁ = m (x - x₁)

y - (-4) = -4 (x - 2)

y + 4 = -4x + 8

y = -4x + 8 - 4

y = -4x + 4

Hope this Helps!!!

User Bertl
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