In order to know if the point (3,4) lies on both lines we need to substitute in each equation the value of the coordinate x and if the point lies on the line the y-coordinate must be the same of the given
For the first equation
x=3
![\begin{gathered} 4(3)-3y=0 \\ 12-3y=0 \\ -3y=-12 \\ y=(-12)/(-3) \\ y=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fk3od4z571nh8kfd3paqg5asv7edxwdtor.png)
The point calculated is (3,4)
For the second equation
x=3
![\begin{gathered} -4(3)+3y=0 \\ -12+3y=0 \\ 3y=12 \\ y=(12)/(3) \\ y=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ep7ct8cr9etig18dfq96qoekyh4p9ttn0o.png)
The point calculated is (3,4)
As we can see the points calculated are congruent with the point given therefore the point (3,4) lies on both lines.
ANSWER
YES