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Ceres, the largest asteroid in the asteroid belt, has a mass of 9.23 x 1020 kilograms and a radius of 474 kilometers. How much would an astronaut of mass 64.5 kilograms weigh on Ceres? Include units in your answer. Answer must be in 3 significant digits.

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Given data:

* The mass of the Ceres is,


M=9.23*10^(20)\text{ kg}

* The mass of the astronaut is,


m=64.5\text{ kg}

* The radius of the Ceres is,


\begin{gathered} R=474\text{ km} \\ R=474*10^3\text{ m} \end{gathered}

Solution:

The gravitational force acting on the astronaut due to the Ceres is,


F=\frac{\text{GMm}}{R^2}

where G is the gravitational force constant,

Substituting the known values,


\begin{gathered} F=(6.67*10^(-11)*9.23*10^(20)*64.5)/((474*10^3)^2) \\ F=(3970.9*10^9)/(224676*10^6) \\ F=0.0177*10^3\text{ N} \\ F=17.7\text{ N} \end{gathered}

The weight of the astronaut on the Ceres is equal to the gravitational force acting on the astronaut.

Thus, the weight of the astronaut on the Ceres is 17.7 N.

User Robertvoliva
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