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"Write the standard equation of a circle with center (3,-4) and radius 3.2"?

"Write the standard equation of a circle with center (3,-4) and radius 3.2&quot-example-1

1 Answer

1 vote

The equation of a circle given the center and the radius is expressed as follows;


(x-h)^2+(y-k)^2=r^2

Note that (h, k) is the center, that is, (3, -4) and the radius is 3.2

The eqy=uation now becomes;


\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-3)^2+(y-\lbrack-4\rbrack)=3.2^2 \\ (x-3)^2+(y+4)^2=10.24 \end{gathered}

Therefore, the first option is the correct answer

User Don Srinath
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