We have 8 sections, numbered from 1 to 8, and 8 servers.
The probability of you being assigned for Section 1 is one into eight (P=1/8) . because we are assuming each of the servers has equal chance of being chosen.
Then, given that you have been assigned to Section 1, there are 7 servers left, including your friend.
Then, there is one into seven chances of your friend being chosen for Section 2 (P=1/7).
We have two events, the first with P=1/8 and the second with P=1/7.
The probability of both of this events happening is the product of their probabilities:
![P=P_1\cdot P_2=(1)/(8)\cdot(1)/(7)=(1)/(56)](https://img.qammunity.org/2023/formulas/mathematics/college/bqeje50cf57rcubkqkx7pe6saeyl4c2xif.png)
The probability of you being assigned to Section 1 and your friend to Section 2 is P=1/56.