Question

How many grams of carbon dioxide are produced when 191 g of methane (CH4) are burned completely as shown in the reaction below:

Answer 1

We have the following chemical reaction:

`CH_4+2O_2\rightarrow CO_2+2H_2O`

Now we calculate how many moles (n) of CH4 react, we use its molar mass:

`M_(CH_4)=M_C+4.M_H=12(g)/(mol)+41.(g)/(mol)=16(g)/(mol)`
`n=(191g)/(16(g)/(mol))=11.93mol`

Now we calculate the moles of CO2 produced. As we can see from the equation for every mol of CH4 that reacts 1 mol of CO2 is produced. So in this case 11.93 moles are produced. Now we calculate the corrisponding mass.

`m_(CO_2)=11.93mol.44(g)/(mol)=524g`

So the answer is 524g.