Question

One 10.0 Ω resistor is wired in series with two 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. What is the total current through the circuit?0.75 A3.0 A0.33 A1.5 A

Answer 1

First, we need to find the equivalent resistance and then we will find the current

R2 and R3 are in parallel so the resistance will be

`R_2R_3=(1)/((1)/(10)+(1)/(10))=5`

then R1, R2R3, and R4 are in series so the resistance equivalent to this circuit will be

then we will use the law of ohm to find the current A1

`I=(60)/(25)=2.4A`

the ammeter A1 will read 2.4A.