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Find the perimeter of the equilateral triangle h = 6x + 8 b = 12x - 4

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Find the perimeter of the equilateral triangle h = 6x + 8 b = 12x - 4​

Perimeter = 3*L (equilateral triangle)

Pythagoras theorem


H^2=C1^2+C2^2


L^2=H^2^{}+(L/2)^2


L^2-\mleft(L/2\mright)^2=H^2

So we need to determine H

6x +8b = 12x - 4

12x-6x= 8b-

User Armin Braun
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