Question

What is the radius of a circle that has a sector of area

Answer 1

ok

Formula

`\text{ A = }(\thetaR^2)/(2)`

Solve for R

`\text{ R = }\sqrt[]{(2A)/(\theta)}`

Substitution

`\text{ R = }\sqrt[]{(2(3\pi))/((2\pi)/(3))}`
`\text{ R = }\sqrt[]{(6\pi)/((2\pi)/(3))}`

`\text{ R = }\sqrt[]{(18\pi)/(2\pi)}`
`\text{ R = }\sqrt[]{9}`

R = 3

The answer is 3, I'm looking for my mistake.