Question

Points of a linear function are listed in the table below.+- 13 -637у6140 13 1What is the slope of the table?Write an equation of the table in point-slope form:Write another point-slope form equation:There will be three extra answers left over!+ y - 61 = 3(x + 13): -32 y - 1 = -3(x - 7).: 3:: y - 40 = -3(x + 6):: y - 13 = 3(x - 3)

Answer 1

`\begin{gathered} \text{slope}=(y_2-y_1)/(x_2-x_1) \\ (-13,61)(-6,40) \\ \text{slope=}(40-61)/(-6-(-13)) \\ \text{slope}=(-21)/(7) \\ \text{slope}=-3 \end{gathered}`
`\begin{gathered} y-y_1=m\mleft(x-x_1\mright) \\ (-13,61) \\ y-61=m(x-(-13)) \\ y-61=m(x+13) \\ y-61=-3(x+13) \\ y-61=-3x-39 \\ y=-3x-39+61 \\ y=22-3x \end{gathered}`
`\begin{gathered} y-y_1=m(x-x_1) \\ (-6,40) \\ y-40=-3(x-(-6)) \\ y-40=-3(x+6) \\ y-40=-3x-18 \\ y=-3x-18+40 \\ y=-3x+22 \\ y=22-3x \end{gathered}`