![4.3\operatorname{\%}]()
1) As it always should be, we need to find the sample space, i.e. the number of total outcomes. We can see that adding them up there are a total of :
![5+7+1+9=12+10=22](https://img.qammunity.org/2023/formulas/mathematics/college/79cucdw0fanzp47ybnczzn99n0si8eu1ff.png)
2) In the table, we can look for the number of favorable events:
![1](https://img.qammunity.org/2023/formulas/mathematics/college/evnrnniir5yjru256yeh5ynmx9yfplp1wo.png)
3) Thus, we can tell that the probability is:
![P(E)=(1)/(23)=0.0434](https://img.qammunity.org/2023/formulas/mathematics/college/jq6wsgkeig7sos9ajl093tgnv0ef6yfwz9.png)
Rounding it off to the nearest tenth as requested we can tell:
![4.3\%](https://img.qammunity.org/2023/formulas/mathematics/college/lz7l01oli58lpcvcqgbaxopjkxbhjhkmmy.png)