199k views
0 votes
A combined total of $68,000 is invested in two bonds that pay 1% and 7% simple interest. The annual interest is $3,260.00. How much is invested in each bond?

User Stravid
by
8.2k points

1 Answer

6 votes

Step-by-step explanation

Assuming that x represents the amount invested at 1% and 68,000-x represent the amount invested at 7%,

The total interest will be given by the following expression:

0.07x + 0.01(68,000-x)= 3,260

Applying the distributive property:

0,07x + 680 -0.01x = 3,260

Subtracting -680 to both sides:

0.07x - 0.01x = 3,260 - 680

Subtracting terms:

0.06x = 2,580

Dividing both sides by -0.06:

x = 2,580/0.06

Simplifying:

x= 43,000

Subtracting 43,000 to 68,000:

68,000-43,000 = 25000

In conclusion, there was invested $25,000 at 1% and $43,000 at 7%

User Dmitriy Selivanov
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories