we have
f(x)=-3+7(x+2)
Remember that
the equation in point-slope form is of the form
y-y1=m(x-x1)
in this problem
f(x)=-3+7(x+2) ------> f(x)+3=7(x+2)
so
point (x1,y1)=(-3,-2)
slope m=7
Part b
g(t)=-(t-5)
the point (x1,y1)=(5,0)
slope m=-1
see the attached figure to better understand the problem