Question

Help please !!! Thank you

Answer 1

Part 1

The rocket splashes down when the height is 0.

`h(t)=-4.9t^2 +82t+101=0\\\\t=(-82 \pm √((-82)^2 -4(4.9)(101)))/(-2(-4.9))\\\\t \approx 17.887 (t > 0)`

Part 2

The beak is at the vertex.

`t=-(82)/(2(-4.9))=(82)/(-9.8)=(410)/(49)\\\\h(410/49)=-4.9(410/49)^2 +82(410/49)+101 \approx 444.061`