Question

Let the function q be given by q(x) = -2(-3x + 2) and let y be the image of x under q. Find the formula for q-1.

Answer 1

Given:-

`q(x)=-2(-3x+2)`

To find:-

`q^(\prime)(x)`

So now ,

`y=-2(-3x+2)`

So now we find the value of x. so we get,

`\begin{gathered} y=-2(-3x+2) \\ y=6x-4^{} \\ y+4=6x \\ (y+4)/(6)=x \end{gathered}`

So the required solution is,

`q^(\prime)(x)=(y+4)/(6)`