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The function has a hole at x = 5 False, you can still solve the function if x = 5, the answer is 0

The function has a slant asymptote at y = 0

The function has a vertical asymptote at x = - 1/3 , since the limit of the function is infinite the vertical asymptote is at x = 1/3

SOLUTION:


\begin{gathered} (-x+5)/(6x-2)=(-x+5)/(2(3x-1)) \\ \text{the denominator will only be zero if x = 1/3 and the limit is infinite} \end{gathered}

The function has a horizontal asymptote at y = 1/6

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