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25.3g C3H8 is burned completely and 68.3g of water is measured as a product. Calculate the percent yield.

1 Answer

5 votes

Answer:

60.48%

Step-by-step explanation

The combustion of propane is expressed as:


C_3H_8+5O_2\rightarrow3CO_2+4H_2O

Determine the moles of water

Moles of water = 68.3/18

Moles of water = 3.79moles

Based on stoichiometry, 1 moles of propane produce 4 moles of water, the moles of propane required will be:


moles\text{ of C}_3H_8=(3.79)/(4)=0.949moles

Determine the mass of propane (theoretical yield)

Mass of propane = 0.949 * 44.1

Mass of propane = 41.83grams

Determine the percentage yield


\begin{gathered} \%yield=(actual)/(theoretical)*100 \\ \%yield=(25.3)/(41.83)*100 \\ \%yield=60.48\% \end{gathered}

Hence the percent yield is 60.48%

User Carlol
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