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What is the diameter of a hemisphere with a volume of 458ft^3, to the nearest tenthof a foot?

User Woninana
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1 Answer

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The formula for getting the volume of a hemisphere is this:


V=(2\pi r^3)/(3)

From this formula, we can solve for the radius then, the diameter of the hemisphere.

Let's plug into the formula above the given volume of the hemisphere.


458ft^3=(2\pi r^3)/(3)

Let's now solve for the radius.

1. Cross multiply both sides of the equation.


458ft^3*3=2\pi r^3
1,374ft^3=2\pi r^3

2. Divide both sides of the equation by 2π.


(1,374ft^3)/(2\pi)=(2\pi r^3)/(2\pi)
218.67889ft^3=r^3

3. Get the cube root on both sides of the equation.


\sqrt[3]{218.67889ft^3}=\sqrt[3]{r^3}\Rightarrow6.0247ft=r

Therefore, the radius of the hemisphere is approximately 6.0247 ft.

Since the diameter is twice the radius, then the diameter is:


D=6.0247ft*2=12.0494ft

Therefore, the diameter of the hemisphere is approximately 12.0 ft.

User Brpaz
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