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5 Write the equation of a line that is parallel to y =-5/4x + 7 and that passes through the point (-4,1).

User Cowhi
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1 Answer

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The equation of the line is given as y = mx + b in slope-intercept form, where m is the slope and b is the y-intercept.

Therefore;


\begin{gathered} y=mx+b \\ \text{When x=-4 and y=1, the parallel equation is;} \\ 1=-(5)/(4)(-4)+b \\ 1=(20)/(4)+b \\ 1=5+b \\ 1-5=b \\ b=4 \end{gathered}

Having determined the y-intercept as 4 for the coordinates (-4, 1), and having in mind that lines that are parallel have the same slope, then;


\begin{gathered} y=mx+b \\ y=-(5)/(4)x+4 \end{gathered}

The equation of the parallel line that passes through the point (-4, 1) is derived as y = -5/4x + 4

User H Boyce
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