Question

Find the equation of a line that passes through (3,10) and is parallel to the graph of y=3x+5. Wrote the equation in slope.intercept form

Answer 1

`\begin{gathered} \text{ Two lines are parallel if the have the same slope and diferent intercept, so } \\ \text{ the line pallalel to y=3x+5} \\ \text{ has the form } \\ y=3x+b \end{gathered}`
`\begin{gathered} \text{ To find b, we replace the values of (3,10) to get it} \\ 10=3(3)+b \\ 10=9+b \\ 10-9=b \\ b=1 \\ \\ \text{The equation is then} \\ y=3x+1 \end{gathered}`