You spin a spinner with 9 equal spaces numbered 1 through 9. What is the probability that the spinner lands on a 5.answers 7/98/91/92/9

asked May 9, 2023 141k views

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$Pr(\text{event)}=\frac{number\text{ of favourable/possible outcomes}}{\text{total number of outcomes}}$
$Pr(\text{spinner lands on 5)=}(1)/(9)$

Hence, the correct option is Option C

Astletron answered May 14, 2023

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