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Which equation has no solution?Group of answer choices4(x + 2) = 4(x+3)−2(x+1)=3x−2−5x4(x+1)−7x=−3(x−1)+1−5(x−7)=2(2x+3)+x+7

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An equation without solutions is an equality which gives a false result like 1=0 or 3=4.

In this case, the first equation has no solution, let's prove it


\begin{gathered} 4(x+2)=4(x+3) \\ 4x+8=4x+12 \\ 8=12 \end{gathered}

As you can observe, the solution is not true which means the equation has no solutions at all.

Therefore, the answer is the first equation.

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