Let us draw a sketch to understand the question
We need to find the coordinates of the point (-x, y)
Since cos(60) = adjacent/hypotenuse
Since the adjacent = x
Since the hypotenuse = 20, then
![cos\left(60\right)=(x)/(20)](https://img.qammunity.org/2023/formulas/mathematics/high-school/qfwxfrdlsaxul33tperc09aa4qbkrr7o82.png)
By using the cross-multiplication
![x=20cos\left(60\right)](https://img.qammunity.org/2023/formulas/mathematics/high-school/emf1cnw2o4r7i3jowai0qqkef3e0tk5h63.png)
Since x must be negative
Since cos(60) = 0.5, then
![\begin{gathered} x=-20\left(0.5\right) \\ x=-10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/u97p6mmmfkslo0l0x9qcmaqmp6rwjiu7ak.png)
Since sin(60) = opposite/hypotenuse
Since the opposite = y
Since the hypotenuse = 20, then
![sin\left(60\right)=(y)/(20)](https://img.qammunity.org/2023/formulas/mathematics/high-school/hg6j99ckixoagpyj8b53db2spd17jjh924.png)
By using the cross multiplication, then
![\begin{gathered} y=20sin\left(60\right) \\ y=20\left((√(3))/(2)\right? \\ y=10√(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/g3tv33vij8gt8m90t6bfk2vmjrkdddp5na.png)
Change it to decimal and round it to the nearest hundredth, then
![y=17.32](https://img.qammunity.org/2023/formulas/mathematics/high-school/hkqgolqnvdgww6jqeb2a47junj79cg810k.png)
The x component of the coordinates is -10
The y component of the coordinate is 17.32