181k views
3 votes
i dont know how to draw the graph as explained. Im actually confused about mostly all of it. I only know how domain and range works and how to tell if its a function.

i dont know how to draw the graph as explained. Im actually confused about mostly-example-1

1 Answer

2 votes

1- You can draw the first line starting at (0,0) and make it as a straight line.

2-

3-

Slope:


\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ \\ m=(7-0)/(8-0)=(7)/(8) \end{gathered}

4- As the line starts in (0,0) the y-intercept (b) is 0, then the equation of the line

(y=mx+b) is:


y=(7)/(8)x

5- Domain: All values of x where the function is defined:


\lbrack0,38\rbrack

Range: All values that the function takes (y-values):


\lbrack0,9.7\rbrack

6-

Rate of change;


\frac{f(end)-f(top)}{xend-\text{xtop}}

First hill:


(4-7)/(11-8)=-(3)/(3)=-1

Second hill:


(5-9.7)/(20-16)=-(4.7)/(4)=-1.175

Third hill:


(4.2-6)/(37-34)=-(1.8)/(3)=-0.6

The greater the rate of change the steeper the hill.

Then, the steeper hill is number 3 (.-0.6 is greather than -1 and -1.175)

7-Draw vertical lines in different parts of the graph, if a vertcal line touches the graph at more than one point then the graph is not a function ( a value of x can not have two different values of y)

It is not a function

i dont know how to draw the graph as explained. Im actually confused about mostly-example-1
i dont know how to draw the graph as explained. Im actually confused about mostly-example-2
i dont know how to draw the graph as explained. Im actually confused about mostly-example-3
i dont know how to draw the graph as explained. Im actually confused about mostly-example-4
i dont know how to draw the graph as explained. Im actually confused about mostly-example-5
User Bijay Yadav
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories