Subtracting mixed numbers with unlike denominators8 \ (9)/(12) - 3 \ (1)/(6)

Question

Subtracting mixed numbers with unlike denominators
`8 \ (9)/(12) - 3 \ (1)/(6)`

Answer 1

Given:

`8(9)/(12)-3(1)/(6)`

We will be subtracting mixed numbers as follows:

First) convert the mixed numbers to fractions as follows:

`\begin{gathered} 8(9)/(12)=(12\cdot8+9)/(12)=(105)/(12) \\ \\ 3(1)/(6)=(6\cdot3+1)/(6)=(19)/(6) \end{gathered}`

Second) make the denominators the same number by finding the lowest common denominator

The least common denominator of 6 and 12 = 12

So, the first fraction will not change

the second fraction will be as follows:

`(19)/(6)=(19\cdot2)/(6\cdot2)=(38)/(12)`

Finally, the subtraction process will be as follows:

`8(9)/(12)-3(1)/(6)=(105)/(12)-(38)/(12)=(105-38)/(12)=(67)/(12)`

Convert the fraction to a mixed number

`(67)/(12)=5(7)/(12)`

So, the answer will be:

`5(7)/(12)`