Given that the two resistors are connected in parallel and each resistance is 14 ohms.
The current in the circuit is I = 0.1 A.
We have to find the voltage of the battery.
Let the voltage be denoted by V.
First, we have to find the equivalent resistance.
![\begin{gathered} (1)/(R_P)=(1)/(14)+(1)/(14) \\ =(2)/(14) \\ R_p=7\text{ ohm} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/l6m09ja9wwxz2d6zfo1gik44wxipqsujx8.png)
The equivalent resistance is 7 ohm.
According to Ohm's law, the voltage can be calculated by the formula
![\begin{gathered} V=R_pI \\ =7*0.1 \\ =0.7\text{ V} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/wa88vu33lm20fsyu9r73xszrgracbvxqsp.png)
Thus, the voltage of the battery is 0.7 V.