Question

The width is 6 5/7 feet the length is 7 3/5 ft what is the area

Answer 1

`\begin{gathered} \text{Area}_(rec\tan gle)=(1786)/(35)ft^2 \\ or \\ 51(1)/(35)ft^2 \end{gathered}`

Step-by-step explanation

the area of a rectangle is given by:

`\text{Area}_(rec\tan gle)=length\cdot width`

Step 1

convert the mixed numbers into fraction numbers, remember:

`a\text{ }(b)/(c)=((a\cdot c)+b)/(c)`

hence,

`\begin{gathered} 6(5)/(7)=((6\cdot7)+5)/(7)=(47)/(7) \\ \text{and} \\ 7(3)/(5)=((7\cdot5)+3)/(5)=(38)/(5) \end{gathered}`

Step 2

now find the area

Let

length=38/5

width=47/7

now, replace.

`\begin{gathered} \text{Area}_(rec\tan gle)=length\cdot width \\ \text{Area}_(rec\tan gle)=(38)/(5)\cdot(47)/(7) \\ \text{Area}_(rec\tan gle)=(1786)/(35) \\ \\ \text{Area}_(rec\tan gle)=(1786)/(35)ft^2 \\ \text{Area}_(rec\tan gle)=51(1)/(35)ft^2 \end{gathered}`

I hope this helsp