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3 votes
Can you help me solve this question ASAP please and thank you

Can you help me solve this question ASAP please and thank you-example-1
User Jack Fan
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1 Answer

3 votes

Let us revise some rules of log


\log (a)+\log (b)=\log (a)(b)
\log (a)-\log (b)=\log ((a)/(b))

Let us use these rules to solve the question

The given expression is


\log (2)-\log (6)

By using the 2nd rule


\log (2)-\log (6)=\log ((2)/(6))=\log ((1)/(3))

Also, we can use the first rule when chang log(6) to -log(1/6)


\begin{gathered} \log (2)-\log (6)=\log (2)-\lbrack-\log ((1)/(6))\rbrack \\ \log (2)-\log (6)=\log (2)+\log ((1)/(6)) \end{gathered}

By using the first rule


\log (2)-\log (6)=\log (2)+\log ((1)/(6))

The correct answers are C and D

User Janstol
by
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