We need to find f(q+1) knowing that f(x) = 6 x + 7
so, we replace x by (q+1) in the functional expression:
f (q+1) = 6 (q + 1) + 7 = 6 q + 6 + 7 = 6 q + 13
So,
f (q+1) = 6 q + 13
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