Question

Factorise the expressions and divide them as directed.​

Answer 1

4z(4z+3)

Explanation:

to understand this

you need to know about:

• algebra

let's solve:

factorize the first expression:

• 26z³(32z²-18)
• 26z³×2(16z²-9)
• 52z³(16z²-9)
• 52z³(4z-3)(4z+3)

divide:

1. 
   `\sf \frac{ \cancel{52 {z}^(3)} \: ^{ \displaystyle ^{4 {z} } } \bcancel{ (4 {z} - 3 )}(4z + 3) ^{ ^{} } } { \cancel{13 {z}^(2)} \: \: \bcancel{(4z - 3) }}`

4z(4z+3)