Question

JOSE is a rhombus and has the perimeter of 8. If JO=3x - 4. What is the value of x?

Answer 1

Recall that the perimeter of a rhombus is given by the following formula:

`P=4s,`

where s is the side length.

Now, we are given that:

`\begin{gathered} s=3x-4, \\ P=8. \end{gathered}`

Therefore:

`8=4(3x-4)\text{.}`

Simplifying the above equation, we get:

`8=12x-16.`

Adding 16 on both sides of the equation, we get:

`\begin{gathered} 8+16=12x-16+16, \\ 24=12x\text{.} \end{gathered}`

Finally, dividing by 12, we get:

`x=(24)/(12)=2.`

Answer:

`x=2.`