Let's make a diagram of the problem
Based on the given information, we can deduct that angle AFC is formed by angles AFB and BFC.
![m\angle AFC=m\angle AFB+m\angle BFC=61+44=105](https://img.qammunity.org/2023/formulas/mathematics/college/e3ojkr4ajf732cs52206dqbdo02h09liw3.png)
Angle AFC measures 105°.
Now, we use the supplementary angles theorem to find angle AFE.
![\begin{gathered} m\angle AFE+m\angle AFB+m\angle BFC=180 \\ m\angle AFE+61+44=180 \\ m\angle AFE=180-44-61=75 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xx9v9wl7yzzj9198m7p81q6u8r26kkda60.png)
Hence, angle AFE measures 75°.
As you can observe in the diagram, angles EFD and BFC are vertical angles, so they are equal.
Hence, angle EFD measures 44°.