Question

I need help with this if anyone can help me!

Answer 1

`y=-60x+600`

Step-by-step explanation

Step 1

find the slope of the line:

if you know 2 points of the line( P1 and P2) you can find the slope using:

`\begin{gathered} \text{slope}=(\Delta y)/(\Delta x)=(y_2-y_1)/(x_2-x_1) \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}`

then, pick 2 points of the line

Let

P1(0,600)

P2(5,300)

replace,

`\begin{gathered} \text{slope}=(\Delta y)/(\Delta x)=(y_2-y_1)/(x_2-x_1)=(300-600)/(5-0)=(-300)/(5)=-60 \\ \text{slope}=-60 \end{gathered}`

Step 2

find the equation of the line using this equation

`\begin{gathered} y-y_1=m(x-x_1) \\ \text{where} \\ m\text{ is the slope and} \\ P1(x_1,y_1) \end{gathered}`

Let

slope=m=-60

P1(0,600)

then, replace

`\begin{gathered} y-y_1=m(x-x_1) \\ y-600=-60(x-0) \\ y-600=-60x \\ \text{add 600 in both sides} \\ y-600+600=-60x+600 \\ y=-60x+600 \end{gathered}`

I hope this helps you