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A softball pitcher swings the ball with an angular velocity of 10.5 rad/s. If the pitcher's arm is 0.65 m long, what is the tangential velocity of the ball just before the pitcher release it?

1 Answer

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Given:

Angular velocity = 10.5 rad/s

Length of arm = 0.65 m

Let's find the tangential velocity of the ball just before the pitcher releases it.

To find the tangential velocity, apply the formula:


v_t=w* r

Where:

w is the angualr velocity = 10.5 rad/s

r is the length of the arm = 0.65 m

To find the tangential velocity, we have:


\begin{gathered} v_t=10.5*0.65 \\ \\ v_t=6.825\text{ m/s} \end{gathered}

Therefore, the tangential velocity of the ball before the pitcher release it is 6.825 m/s.

ANSWER:

6.825 m/s

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