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Find the equation of a line perpendicular to y=-x-1 that contains the point (1, 2)

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Answer:

y = x + 1

Step-by-step explanation:

The standard form of expressing the equation of a line is expressed as:

y - y0 = m(x-x0) where;

m is the slope

(x0, y0) is the point on the line

Given the line y = - x - 1

mx = -x

m = -1

The slope of the line perpendicular to the line will be 1

Given the point (1, 2), the required equation will be expressed as:

y - y0 = m(x - x0)

y - 2 = 1(x - 1)

y - 2 = x - 1

y = x - 1 + 2

y = x + 1

Hence the equation of a line perpendicular to y=-x-1 that contains the point (1, 2) is

y = x + 1

User Essex Boy
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