Given:
a.) One troop member sold tickets for 20 crab meals and 8 vegetarian meals, with total receipts of $796.
b.) Another sold tickets for 26 crab meals and 34 vegetarian meals, bringing in a total of $1,554.
Let,
x = cost of a crab meal
y = cost of a vegetarian meal
Let's solve this using the Substitution Method.
We get,
Equation 1: One troop member sold tickets for 20 crab meals and 8 vegetarian meals, with total receipts of $796.
Equation 2: Another sold tickets for 26 crab meals and 34 vegetarian meals, bringing in a total of $1,554.
Substitute Eq. 1 to Eq. 2
20x + 8y = 796
8y = 796 - 20x
y = (796 - 20x)/8
y = 199/2 - 5x/2
26x + 34y = 1,554
26x + 6,766/2 - 170x/2 = 1,554
26x + 3,383 - 85x = 1,554
-59x = 1,554 - 3,383
-59x = -1,829
-59x/-59 = -1,829/-59
x = 31 = $31
Therefore, the crab meal costs $31.
For the vegetarian meal,
20x + 8y = 796
20(31) + 8y = 796
620 + 8y = 796
8y = 796 - 620
8y = 176
8y/8 = 176/8
y = 22 = $22
Therefore, the vegetarian meal costs $22.