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If y varies directly as x, and y = 25 when x = 15, find x when y = 60.

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\begin{gathered} (y)/(x)=(25)/(15)=(5)/(3) \\ \text{and this rate remain the same for all the possible values of y and x, so} \\ (60)/(x)=(5)/(3)\rightarrow x=60\cdot(3)/(5)=36 \end{gathered}

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