Question

A sprinter runs all the way around a 400.0 m oval track, ending back where she started, in 52 seconds. What was her speed?A. 0.13 m/sB. 7.7 m/sC. 1.3 m/sD. 0 m/s

Answer 1

Given data:

* The total distance traveled by the sprinter is d = 400 m.

* The total time taken in the given case is t = 52 seconds.

Solution:

The speed in the given case is,

`s=\frac{\text{total distance traveled }}{\text{total time taken}}`

Substituting the known values,

`\begin{gathered} s=(400)/(52) \\ s=7.69\text{ m/s} \\ s\approx7.7\text{ m/s} \end{gathered}`

Thus, the speed of the sprinter is 7.7 m/s.

Hence, option B is the correct answer.